Order by should be in last

select name, sum(score) 
from submissions 
inner join hacker on submissions.hacker_id = hacker.hacker_id
group by submissions.hacker_id
having sum(score) > 50 
order by sum(score) desc

按照应该在最后进行排序

选择 名称, 总分
从 提交
内连接 黑客 on 提交.黑客编号 = 黑客.黑客编号
分组 按 提交.黑客编号
筛选 总分 > 50 
排序 按 总分 降序

您的order by应该在您的having之后。即：

select 
    name, 
    sum(score) 
from 
    submissions 
inner join 
    hacker on submissions.hacker_id = hacker.hacker_id
group by 
    submissions.hacker_id
having 
    sum(score) > 50 
order by 
    sum(score) desc