<p>我正在尝试在一个Node.js Express服务器中使用GraphQL和mysql。</p> <p>但是每次运行查询时都会出现以下错误：</p> <p>错误信息如下：</p> <pre class="brush:php;toolbar:false;">{ "errors": [ { "message": "Expected Iterable, but did not find one for field \"RootQueryType.getAllGoals\".", "locations": [ { "line": 2, "column": 3 } ], "path": [ "getAllGoals" ] } ], "data": { "getAllGoals": null } }</pre> <p>这是我的GraphQL查询：</p> <pre class="brush:php;toolbar:false;">query { getAllGoals { title progress goal } }</pre> <p>我从"SELECT * FROM (我的表)"中得到了预期的结果，但是当我尝试将其作为GraphQL的resolver返回时，它给了我一个错误，如下所示：</p> <pre class="brush:php;toolbar:false;">const RootQuery = new GraphQLObjectType({ name: "RootQueryType", fields: { getAllGoals: { type: new GraphQLList(GoalType), resolve(parent, args) { return db.query("SELECT * FROM myTable", (err, result) => { if (err) throw err console.log(JSON.parse(JSON.stringify(result))) return JSON.parse(JSON.stringify(result)) }) } } } })</pre> <p>我已经检查过我的GraphQLObjectType GoalType是否有任何冲突，但是没有发现任何问题。</p>

async resolve(parent, args) {
                var p = new Promise((resolve, reject) => {
                    db.query("SELECT * FROM myTable", (err, result) => {
                        console.log(JSON.parse(JSON.stringify(result)))
                        resolve(JSON.parse(JSON.stringify(result)))
                    })
                })
                return p
            }