我想在一个数组上运行一个过滤器或缩减操作，并根据像这个例子中的'name'属性删除数组中的所有重复项。我看到的例子是遍历数组并保留其中一个重复项，但在我的情况下，我需要将它们分开，并将重复项以数组的形式返回给用户以更正数据，并处理其他剩余项。我在下面给出了一个示例数组和期望的结果数组。如果有人能给我一个如何做到这一点的例子，我将非常感激！谢谢！
const customers = [ { id:1, name: "John", address="123 street"}, { id:2, name: "Alex", address="456 street"}, { id:3, name: "John", address="674 street"}, { id:4, name: "Stacy", address="534 street"}, { id:5, name: "Blair", address="634 street"} ]; 这将给我以下两个数组：
[ { id:1, name: "John", address="123 street"},, { id:3, name: "John", address="674 street"}, ] 和 [ { id:2, name: "Alex", address="456 street"}, { id:4, name: "Stacy", address="534 street"}, { id:5, name: "Blair", address="634 street"} ] 
尝试一下
const customers = [ { id: 1, name: "John", address: "123 street" }, { id: 2, name: "Alex", address: "456 street" }, { id: 3, name: "John", address: "674 street" }, { id: 4, name: "Stacy", address: "534 street" }, { id: 5, name: "Blair", address: "634 street" } ]; const nameMap = new Map(); const nonUniqueCustomers = []; const uniqueCustomers=[]; customers.forEach(customer => { if (!nameMap.has(customer.name)) { nameMap.set(customer.name, []); } nameMap.get(customer.name).push(customer); }); nameMap.forEach(customers => { if (customers.length > 1) { nonUniqueCustomers.push(...customers); }else{ uniqueCustomers.push(...customers) } }); console.log("非唯一顾客:", nonUniqueCustomers); console.log("唯一顾客:", uniqueCustomers);