javascript 如何对两个数组进行比较

Question

数组a {代码...} 数组b是在数组a的一部分 {代码...} 数组c是在数组b的基础上进行修改 {代码...} 现在需要最后的结果为key:1被修改，key:2被删除，key:3，key:4，key:5无变化保留，key:22被添加 {代码...} 请问一...

滿天的星座 · Answer

你是要比较还是合并？合并用 deepmerge 很方便

PHP中文网 · Answer

学习ing · Answer

var a = [{key:1,name:'name1'},{key:2,name:'name2'},{key:3,name:'name3'},{key:4,name:'name4'},{key:5,name:'name5'}];
var b = [{key:1,name:'name1'},{key:2,name:'name2'}];
var c = [{key:1,name:'name11'},{key:22,name:'name22'}];
var d = [];
d = $.extend(a,(b,c));
console.log(d);

extend方法跟git 的merge差不多
我那样写应该会得到你最后想要的那种结果

给我你的怀抱 · Answer

typecho · Answer

如果找不到好的工具，或者不想污染命名空间，那就把数组解耦，这样应该可以满足你的要求

let a = [{ key: 1, name: 'name1' }, { key: 3, name: 'name3' }, { key: 2, name: 'name2' }, { key: 4, name: 'name4' }, { key: 5, name: 'name5' }];
let b = [{ key: 1, name: 'name1' }, { key: 2, name: 'name2' }];
let c = [{ key: 22, name: 'name22' }, { key: 1, name: 'name11' }];
let akeys = a.map(x => x.key);
let aname = a.map(x => x.name)
let bkeys = b.map(x => x.key)//1,2
let bname = b.map(x => x.name)
let ckeys = c.map(x => x.key)//1,22
let cname = c.map(x => x.name)

ckeys.forEach(function (key, index) {
  if (bkeys.includes(key))
    a[akeys.indexOf(key)].name = cname[ckeys.indexOf(key)]
  else {
    a[akeys.indexOf(bkeys[1])].key = key
    a[akeys.indexOf(bkeys[1])].name = cname[ckeys.indexOf(key)]
  }
})
console.log(a)

漂亮男人 · Answer

给你一段代码拿去想象（只适用与数组合并），将下面的代码拿到控制台输出一下就行了

function arrayExtends(){
    var arrs = Array.prototype.slice.call(arguments);

    if(arrs.length < 2){
        return arrs[0];
    }

    var save = arrs.pop(),
        now;

    while(now = arrs.pop()){
        for( var i = 0 , len = save.length; i < len; i++ ){
            now[i] = save[i];
        }
        save = now;
    }

       return save;
}
arrayExtends([1,2,3,6,7],[4,5,{hello:"world"}],[{key:1,name:"zz"}]);

然后修改下适应你的需求：

function arrayExtends(){
    var arrs = Array.prototype.slice.call(arguments);

    if(arrs.length < 2){
        return arrs[0];
    }

    var save = arrs.pop(),
        now;

    while(now = arrs.pop()){
        for( var i = 0 , len = save.length; i < len; i++ ){
            now[i] = save[i];
        }
        save = now;
    }

    var result = save.sort(function(a,b){
        return a.key - b.key;
    });

       return result;
}
arrayExtends([{key:1,name:"zz"}],[{key:2,name:"zz"},{key:3,name:"zz"}]);