Two elements giving the maximum sum in an array means, we have to find two largest array elements which will eventually give the maximum sum possible.
In this article we will see how we can find the maximum sum of two elements in Java.
Suppose we have the below array
[10, 2, 3, -5, 99, 12, 0, -1]
In this array the largest element is 99 and second largest is 12.
Max sum = 99 + 12
因此，这个数组中两个元素的最大和为111。
Suppose we have the below array
[556, 10, 259, 874, 123, 453, -96, -54, -2369]
在这个数组中，最大的元素是874，第二大的元素是556。
Max sum = 874+556
因此，该数组中两个元素的最大和为1430。
Suppose we have the below array
[55, 10, 29, 74, 12, 45, 6, 5, 269]
在这个数组中，最大的元素是269，第二大的元素是74。
Max sum= 269+74
因此，该数组中两个元素的最大和为343。
步骤 1 − 使用 for 循环在数组中找到最大和第二大的元素。
步骤 2 - 找到它们的和。
Step 3 − Print the sum.
Step 1 − Sort the array elements.
Step 2 −Take the last and second last element of the array.
Step 3 − Find their sum.
Step 4 − Print the sum.
To sort the array we need to use the sort( ) method of the Arrays class of java.util package.
Following is the syntax to sort any array in ascending order using the method
<span class="typ">Arrays</span><span class="pun">.</span><span class="pln">sort</span><span class="pun">(</span><span class="pln">array_name</span><span class="pun">);</span>
Where, ‘array_name’ refers to the array that you want to sort.
We have provided the solution in different approaches.
使用for循环找到最大的和
Find The Largest Sum Using Arrays.sort
让我们逐一查看程序及其输出。
In this approach, we use a for loop to iterate through the array elements to find out the largest and second largest element. These two elements will give the maximum sum.
public class Main {
public static void main(String[] args) {
// The array elements
int arr[] = { 10, 2, 3, -5, 99, 12, 0, -1 };
// Storing the first element in both variables
int first = arr[0], second = arr[0];
// For loop to iterate the elements from 1 to n
// to find the first largest element
for (int i = 0; i < arr.length; i++) {
// If array element is larger than current largest element, then swap
if (arr[i] > first)
first = arr[i];
}
// For loop to iterate the elements from 1 to n
// to find the second largest element
for (int i = 0; i < arr.length; i++) {
// If array element is larger than current largest element and not equals to
// largest element, then swap
if (arr[i] > second && arr[i] != first)
second = arr[i];
}
// Print the sum
System.out.println("Largest sum = " + (first + second));
System.out.println("The elements are " + first + " and " + second);
}
}
Largest sum = 111 The elements are 99 and 12
在这种方法中，我们使用Arrays.sort()方法对数组进行排序。然后我们取最后一个和倒数第二个索引上的元素。由于数组已经排序过了，这两个元素将给出最大的和。
import java.util.Arrays;
public class Main {
public static void main(String[] args) {
// The array elements
int arr[] = { 10, 2, 3, -5, 99, 12, 0, -1 };
// Sort the array using the sort method from array class
Arrays.sort(arr);
// Storing the last element as largest and second last element as second largest
int first = arr[arr.length - 1], second = arr[arr.length - 2];
// Print the maximum sum
System.out.println("Maximum sum = " + (first + second));
System.out.println("The elements are " + first + " and " + second);
}
}
Maximum sum = 104 The elements are 99 and 12
在本文中，我们探讨了在Java中找到数组中具有最大和的两个元素的不同方法。
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