在C/C++中的Power函数

double pow(double a , double b)

#include <stdio.h>
#include <math.h>
int main() {
   double x = 6.1, y = 2;
   double result = pow(x, y);
   printf("%f raised to the power of %f is %f \n" ,x,y, result );
   // Taking integers
   int a = 5 , b = 2;
   int square = pow(a,b);
   printf("%d raised to the power of %d is %d \n", a,b, square );
   return 0;
}

6.100000 raised to the power of 2.000000 is 37.210000
5 raised to the power of 2 is 25