在本节中，我们将看到如何生成任意长度的所有可能字符串，这将采用每个字符的组合来生成字符串。例如，如果字符串是ABC，则它将生成 - {A，B，C，AB，BA，BC，CB，CA，AC，ABC，ACB，BAC，BCA，CAB，CBA}
让我们看一个例子来理解。
Begin
n := length of the string str
count is 2^n – 1
for each number 0 to count, do
sub_str := empty string
for j in range 0 to n, do
if jth bit of the counter is set, then
concatenate jth character of str with sub_str
end if
done
repeat:
print sub_string
until next permutation of sub_string is not completed
done
End#include <iostream>
#include <algorithm>
#include <cmath>
using namespace std;
void printAllString(string str) {
int n = str.size();
unsigned int count = pow(2, n);
for (int counter = 1; counter <count; counter++) { //generate 2^n - 1 strings
string subs = "";
for (int j = 0; j < n; j++) {
if (counter & (1<<j)) //when the jth bit is set, then add jth character
subs.push_back(str[j]);
}
do{
cout << subs << endl;
}
while (next_permutation(subs.begin(), subs.end()));
}
}A B AB BA C AC CA BC CB ABC ACB BAC BCA CAB CBA D AD DA BD DB ABD ADB BAD BDA DAB DBA CD DC ACD ADC CAD CDA DAC DCA BCD BDC CBD CDB DBC DCB ABCD ABDC ACBD ACDB ADBC ADCB BACD BADC BCAD BCDA BDAC BDCA CABD CADB CBAD CBDA CDAB CDBA DABC DACB DBAC DBCA DCAB DCBA
以上是给定一个字符串，将其组成的所有可能长度的字符串都列出来的详细内容。更多信息请关注PHP中文网其他相关文章！
