PHP快手API接口开发实战：如何实现视频的下载和转码

// 获取视频信息
$videoUrl = 'http://xxxxx'; // 快手视频的URL地址
$apiUrl = 'http://xxxxx/video/info?videoUrl=' . urlencode($videoUrl);
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $apiUrl);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$response = curl_exec($ch);
curl_close($ch);

// 解析返回的JSON数据
$data = json_decode($response, true);
$videoUrl = $data['video']['srcNoMark']['url'];

// 下载视频
$savePath = '/path/to/save/video.mp4'; // 保存路径及文件名
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $videoUrl);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$videoData = curl_exec($ch);
curl_close($ch);
file_put_contents($savePath, $videoData);

$videoPath = '/path/to/video.mp4'; // 待转码的视频路径
$outputPath = '/path/to/converted_video.mp4'; // 转码后的视频路径

// 使用FFmpeg进行转码
$cmd = "ffmpeg -i $videoPath -codec copy $outputPath";
exec($cmd);