本文主要和大家分享一个关于javascript二维数组的面试题，希望能帮助到大家。给定一个二维数组，实现一个功能函数 fn，向这个函数中传递这个二维数组的一个坐标，如果这个坐标的值为 ”1“，将返回和这个坐标所有相连的并且坐标值为1坐标。
例如,传递了 fn([3,4])得到的结果为：
[[3,4],[4,4],[5,4],[6,4],[7,4],[8,4],[8,5],[8,6]]
var arr =[ [0,0,0,0,0,0,0,0,0,0,0], [0,0,0,0,0,0,0,0,0,0,0], [0,0,0,0,0,0,0,0,0,0,0], [0,0,0,0,1,0,0,0,1,0,0], [0,0,0,0,1,0,0,0,1,0,0], [0,0,0,0,1,0,0,0,1,0,0], [0,0,0,0,1,0,0,0,0,0,0], [0,0,0,0,1,0,0,0,0,0,0], [0,0,0,0,1,1,1,0,0,0,0], [0,0,0,0,0,0,0,0,0,0,0], [0,0,0,0,0,0,0,0,0,0,0], ] ;
解答思路：宽度优先遍历即可。供参考，相连条件没给出且当做是横竖方向:
var arr =[
[0,0,0,0,0,0,0,0,0,0,0],
[0,0,0,0,0,0,0,0,0,0,0],
[0,0,0,0,0,0,0,0,0,0,0],
[0,0,0,0,1,0,0,0,1,0,0],
[0,0,0,0,1,0,0,0,1,0,0],
[0,0,0,0,1,0,0,0,1,0,0],
[0,0,0,0,1,0,0,0,0,0,0],
[0,0,0,0,1,0,0,0,0,0,0],
[0,0,0,0,1,1,1,0,0,0,0],
[0,0,0,0,0,0,0,0,0,0,0],
[0,0,0,0,0,0,0,0,0,0,0],
]
function fn ([x, y]) {
if (arr[x][y] !== 1) return false
const queue = [[x, y]]
const memo = arr.map(row => new Array(row.length).fill(false))
const direction = [
[-1, 0],
[1, 0],
[0, -1],
[0, 1],
]
while(queue.length > 0) {
const [x, y] = queue.pop()
direction.forEach(([h, v]) => {
const newX = x + h
const newY = y + v
if (arr[newX][newY] === 1 && !memo[newX][newY]) {
memo[newX][newY] = true
queue.push([newX, newY])
}
})
}
const result = []
for (let i = 0; i < arr.length; i++) {
for (let j = 0; j < arr[i].length; j++) {
if(memo[i][j]) {
result.push([i, j])
}
}
}
return result
}
console.log(fn([3,4]))借鉴前两位 对象+递归实现
function fn(point) {
var memo = {}, result = [], direction = [[-1, 0],[1, 0],[0, -1],[0, 1]]
function dg([x, y]) {
result.push(memo[x + "," + y] = [x, y]);
direction.forEach(([h, v]) => {
const newX = x + h
const newY = y + v
if (arr[newX][newY] === 1 && !memo[newX + "," + newY]) {
dg([newX, newY]);
}
})
}
dg(point);
return result;
}var arr =[
[0,0,0,0,0,0,0,0,0,0,0],
[0,0,0,0,0,0,0,0,0,0,0],
[0,0,0,0,0,0,0,0,0,0,0],
[0,0,0,0,1,0,0,0,1,0,0],
[0,0,0,0,1,0,0,0,1,0,0],
[0,0,0,0,1,0,0,0,1,0,0],
[0,0,0,0,1,0,0,0,0,0,0],
[0,0,0,0,1,0,0,0,0,0,0],
[0,0,0,0,1,1,1,0,0,0,0],
[0,0,0,0,0,0,0,0,0,0,0],
[0,0,0,0,0,0,0,0,0,0,0],
]
function fn ([x, y]) {
if (arr[x][y] !== 1) return false
const queue = [[x, y]]
const result = [[x,y]]
const memo = arr.map(row => new Array(row.length).fill(false))
const direction = [
[-1, 0],
[1, 0],
[0, -1],
[0, 1],
]
while(queue.length > 0) {
const [x, y] = queue.pop()
direction.forEach(([h, v]) => {
const newX = x + h
const newY = y + v
if (arr[newX][newY] === 1 && !memo[newX][newY]) {
memo[newX][newY] = true
queue.push([newX, newY])
result.push([newX, newY])
}
})
}
return result
}相关推荐：
定义JavaScript二维数组采用定义数组的数组来实现_基础知识
以上是javascript二维数组的面试题的详细内容。更多信息请关注PHP中文网其他相关文章！
