关于foreach输出问题

$sql1="select * from y_cate order by asc";
$result1=mysql_fetch_array(mysql_query($sql1));
var_dump($result1);
foreach($result1 as $ke=>$a){
    echo $a."
";
}
?>
我想用foreach 来循环输出cate表的所有数据，为什么只输出一条数据的？求解答

回复讨论(解决方案)

$sql1="select * from y_cate order by asc";$result1 = mysql_query($sql1);while($row = mysql_fetch_array($result1)) {  foreach($row as $ke=>$a){    echo $a."<br>";  }}

$sql1="select * from y_cate order by asc";
$result1=mysql_fetch_array(mysql_query($sql1));
var_dump($result1);
foreach($result1 as $ke=>$a){
echo $a."
";
}
?>
我想用foreach 来循环输出cate表的所有数据，为什么只输出一条数据的？求解答 1. 你的sql语句不会报错？order by asc，没有排序字段;
2. 没有执行 sql语句。mysql_query($sql1).

$sql1="select * from y_cate order by asc";
$result1=mysql_fetch_array(mysql_query($sql1));
var_dump($result1);
foreach($result1 as $ke=>$a){
echo $a."
";
}
?>
我想用foreach 来循环输出cate表的所有数据，为什么只输出一条数据的？求解答 1. 你的sql语句不会报错？order by asc，没有排序字段;
2. 没有执行 sql语句。mysql_query($sql1). 手误手误 ?

select * from y_cate order by asc的问题

order by没有指定字段,会报错:#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near "..........

$sql1="select * from y_cate order by asc";$result1 = mysql_query($sql1);while($row = mysql_fetch_array($result1)) {  foreach($row as $ke=>$a){    echo $a."<br>";  }}

select * from y_cate order by asc的问题

order by没有指定字段,会报错:#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near "..........
亲，手敲的代码，手误漏掉了。请问我问的问题怎么解决

$sql1="select * from y_cate order by asc";$result1 = mysql_query($sql1);while($row = mysql_fetch_array($result1)) {  foreach($row as $ke=>$a){    echo $a."<br>";  }}

while($row = mysql_fetch_array($result1,MYSQL_ASSOC)) {
  foreach($row as $ke=>$a){
    echo $a."
";
  }
}

或者就用mysql_fetch_assoc/mysql_fetch_row