A1 2014-10-1 10:00:00
A2 2014-10-2 14:00:00
B1 2014-10-4 13:00:00
B2 2014-10-5 15:00:00
A1为开始时间，A2为结束时间，B1为开始时间，B2为结束时间
现在有时间 C1-C2
如何判断C1-C2，如果在A1-A2或者B1-B2里面或者有交叉，出现弹框提示。
转换成时间戳 然后比较大小
观察一个事实
$ar = array( 'A1' => '2014-10-1 10:00:00', 'A2' => '2014-10-2 14:00:00', 'B1' => '2014-10-4 13:00:00', 'B2' => '2014-10-5 15:00:00',);$ar['C1'] = '2014-10-3 13:00:00';$ar['C2'] = '2014-10-5 13:00:00';asort($ar);print_r($ar);
Array( [A1] => 2014-10-1 10:00:00 [A2] => 2014-10-2 14:00:00 [C1] => 2014-10-3 13:00:00 [B1] => 2014-10-4 13:00:00 [C2] => 2014-10-5 13:00:00 [B2] => 2014-10-5 15:00:00)
观察一个事实
$ar = array( 'A1' => '2014-10-1 10:00:00', 'A2' => '2014-10-2 14:00:00', 'B1' => '2014-10-4 13:00:00', 'B2' => '2014-10-5 15:00:00',);$ar['C1'] = '2014-10-3 13:00:00';$ar['C2'] = '2014-10-5 13:00:00';asort($ar);print_r($ar);
Array( [A1] => 2014-10-1 10:00:00 [A2] => 2014-10-2 14:00:00 [C1] => 2014-10-3 13:00:00 [B1] => 2014-10-4 13:00:00 [C2] => 2014-10-5 13:00:00 [B2] => 2014-10-5 15:00:00)
无论有多少数据，算法都是不变的
只要依次检查键名，同组的“开始”和“结束”不相邻就是有交叉或嵌套
不写具体代码的原因是：你的情况远比示例复杂，写了你也套不上去。关键在于理解
