【分享】PHP int 超大溢出整数的 加减运算函数，如果有更好的方法欢迎探讨
分享一个溢出整数加减的运算函数，刚刚写的，对于溢出的整数可以用这个来进行加减运算。
遗憾的几点是：
<br /> 一代码太多；<br /> 二只有加减运算，乘除取余都没有；<br />
<br /> mysql> SELECT 11234123413241341234123412341234+1;<br /> +------------------------------------+<br /> | 11234123413241341234123412341234+1 |<br /> +------------------------------------+<br /> | 11234123413241341234123412341235 |<br /> +------------------------------------+<br /> 1 row in set (0.00 sec)<br /> <br /> <br /> mysql> SELECT 11234123413241341234123412341234*12341234123;<br /> +----------------------------------------------+<br /> | 11234123413241341234123412341234*12341234123 |<br /> +----------------------------------------------+<br /> | 138642947209487270472850788378836360727782 |<br /> +----------------------------------------------+<br /> 1 row in set (0.00 sec)<br /> <br /> <br />
<br>
/* big int operate [by fuzb 20130826] */<br>
function bigintO($num1,$op,$num2)<br>
{<br>
$arr = array();<br>
$endop = '';<br>
$num1o = $num1;<br>
$num2o = $num2;<br>
if($num1
{<br>
$c1 = -1;<br>
$num1 = preg_replace('/^(-)/','',$num1);<br>
<br>
} else {<br>
$c1 = 1;<br>
}<br>
<br>
if($num2
{<br>
$c2 = -1;<br>
$num2 = preg_replace('/^(-)/','',$num2);<br>
} else {<br>
$c2 = 1;<br>
}<br>
<br>
$len1 = strlen($num1);<br>
$len2 = strlen($num2);<br>
$len = max(strlen($num1),strlen($num2));<br>
if($len1
if($len2
<br>
<br>
if($op == '+')<br>
{<br>
if($c1 == $c2)<br>
{ <div class="clear">
</div>
