如何通过PHP中的引用传递变量？

使用&符号在函数参数前可实现引用传递，使函数直接修改原始变量。例如定义function increment(&$value) { $value ; }后，调用increment($number)会改变$number的值；引用传递无需在调用时使用&，仅需在函数声明中使用；还可通过&function &getGlobalRef()返回引用，使$ref =& getGlobalRef()指向静态变量并修改其值。

In PHP, variables are passed by value by default, meaning a copy of the variable is used within a function. To pass variables by reference instead, you use the ampersand (&) symbol before the parameter name in the function definition. This allows the function to modify the original variable directly.

Use & in Function Parameters

To pass a variable by reference, add & before the parameter in the function declaration. Any changes made to the parameter inside the function will affect the original variable.

Passing References When Calling Functions

You don't need to use & when calling the function — it's only required in the parameter definition. The caller just passes the variable normally, and PHP handles it as a reference because of how the function is defined.

Returning References

You can also return a reference from a function. This is useful when you want to assign a reference to a global or static variable. Use & before the function name and when assigning the return value.

Basically, just use & in the parameter list to pass by reference. It’s not complex, but it does let functions alter external variables directly, so use it carefully.

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