<span>W = window, </span> <span>D = document; </span> <span>//set the window to widgets dimensions </span> <span>var winH = 400, //allow for window padding and header </span> winW <span>= 400, </span> winT <span>= 400, </span> winL <span>= 400; </span> <span>//set the content </span> <span>var windowName = 'Widget', // should not include space for IE </span> path <span>= W.location.path, </span> windowOptions <span>= 'location=0,status=0,toolbar=0,dependent=1,resizable=1,menubar=0,screenX=' + winL + ',screenY=' + winT + ',width=' + winW + ',height=' + winH, </span> that <span>= this; </span> <span>//note path needs to be in the same domain... </span> <span>//open the window </span> that<span>._Window = window.open(path, windowName, windowOptions); </span> that<span>._Interval = window.setInterval(function () { </span> <span>if (that._Window.closed) { </span> <span>window.clearInterval(that._Interval); </span> <span>//code to run when window is closed </span> <span>} </span> <span>}, 1000);</span>
在JavaScript中创建一个弹出窗口非常简单。您可以使用window.open()方法。此方法创建一个新窗口并返回对其的引用。这是一个基本示例: )这是'mywindow'
var mywindow = window.open(“”,“ mywindow”,“ width = 200,height = 100”);
在此示例中,window.open()方法采用三个参数:打开页面的URL(左)在这里空白以创建一个空窗口),窗口的名称和一个指示窗口特征的字符串(例如其宽度和高度)。
>如何控制弹出窗口的大小和位置? 🎜>
>我可以在弹出窗口中加载特定的URL窗口?
var mywindow = window.open(“”,“ mywindow”,“ width = 500,高度= 600,resizizable = no”);
>
弹出窗口仍然打开?
if(!myWindow.claped){
//窗口仍然打开
}
hello,world!
”); var mywindow = window.open(“”,“ mywindow”,“ width = 500,高度= 600,工具栏= no”);
始终处于顶部?
是的,可以检测使用何时使用窗口关闭弹出窗口。 Onunload事件。当窗口即将卸载其资源时,该事件将发射。以下是一个示例:
};
>
>
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