如何使用谓词查找 Java 8 流中的第一个不匹配？

import java.util.stream.Stream;

public class LimitStreamByPredicate {

    public static void main(String[] args) {
        // Create an infinite stream of numbers
        Stream<Integer> numbers = Stream.iterate(1, n -> n + 1);

        // Predicate to check if a number is less than 10
        Predicate<Integer> predicate = n -> n < 10;

        // Create a limited stream using iteration
        Stream<Integer> result = numbers.iterator()
                .takeWhile(predicate)
                .map(n -> n);

        // Print the limited stream
        result.forEach(System.out::println);
    }
}