为什么我的 Java HttpClient 文件上传到 PHP 服务器失败，如何使用 MultipartEntity 修复它？-php教程-PHP中文网

为什么我的 Java HttpClient 文件上传到 PHP 服务器失败，如何使用 MultipartEntity 修复它？

Mary-Kate Olsen

发布： 2024-12-19 15:44:10

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Why is my Java HttpClient file upload to a PHP server failing, and how can I fix it using MultipartEntity?

使用 PHP 通过 Java 的 HttpClient 上传文件

在尝试使用 PHP 将文件从 Java 上传到 Apache 服务器时，利用 Jakarta 创建了一个 Java 应用程序HttpClient 库版本 4.0 beta2。然而，PHP 脚本无法识别上传的文件，导致 $_FILES 数组为空。

Java 实现

最初的 Java 代码不正确，从下面的修改版本可以看出：

import java.io.File;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.HttpVersion;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.entity.mime.MultipartEntity;
import org.apache.http.entity.mime.content.ContentBody;
import org.apache.http.entity.mime.content.FileBody;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.params.CoreProtocolPNames;
import org.apache.http.util.EntityUtils;

public class PostFile {
  public static void main(String[] args) throws Exception {
    HttpClient httpclient = new DefaultHttpClient();
    httpclient.getParams().setParameter(CoreProtocolPNames.PROTOCOL_VERSION, HttpVersion.HTTP_1_1);

    HttpPost httppost = new HttpPost("http://localhost:9001/upload.php");
    File file = new File("c:/TRASH/zaba_1.jpg");

    MultipartEntity mpEntity = new MultipartEntity();
    ContentBody cbFile = new FileBody(file, "image/jpeg");
    mpEntity.addPart("userfile", cbFile);

    httppost.setEntity(mpEntity);
    System.out.println("executing request " + httppost.getRequestLine());
    HttpResponse response = httpclient.execute(httppost);
    HttpEntity resEntity = response.getEntity();

    System.out.println(response.getStatusLine());
    if (resEntity != null) {
      System.out.println(EntityUtils.toString(resEntity));
    }
    if (resEntity != null) {
      resEntity.consumeContent();
    }

    httpclient.getConnectionManager().shutdown();
  }
}

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主要区别在于 MultipartEntity 的利用，它可以正确处理文件

PHP 脚本

PHP 脚本保持不变：

<?php
if (is_uploaded_file($_FILES['userfile']['tmp_name'])) {
  echo "File ". $_FILES['userfile']['name'] ." uploaded successfully.\n";
  move_uploaded_file ($_FILES['userfile'] ['tmp_name'], $_FILES['userfile'] ['name']);
} else {
  echo "Possible file upload attack: ";
  echo "filename '". $_FILES['userfile']['tmp_name'] . "'.";
  print_r($_FILES);
}
?>

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