json_encode 返回描述字段为空
问题：
下面的 PHP 代码无法对 JSON 响应中的“描述”字段进行编码，返回 NULL
include('db.php');
$result = mysql_query('SELECT * FROM `staff` ORDER BY `id` DESC LIMIT 2') or die(mysql_error());
$rows = array();
while($row = mysql_fetch_assoc($result)){
$rows[] = $row;
}
echo json_encode($rows);数据库架构：
CREATE TABLE `staff` ( `id` int(11) NOT NULL AUTO_INCREMENT, `name` longtext COLLATE utf8_unicode_ci, `description` longtext COLLATE utf8_unicode_ci, `icon` longtext COLLATE utf8_unicode_ci, `date` longtext COLLATE utf8_unicode_ci, `company` longtext COLLATE utf8_unicode_ci, `companyurl` longtext COLLATE utf8_unicode_ci, `appurl` longtext COLLATE utf8_unicode_ci, PRIMARY KEY (`id`) ) ENGINE=MyISAM AUTO_INCREMENT=5 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci
输出：
[{"id":"4","name":"Noter 2","description":null,"icon":"http:\/\/images.apple.com\/webapps\/productivity\/images\/noter2_20091223182720-thumb.jpg","date":"1262032317","company":"dBelement, LLC","companyurl":"http:\/\/dbelement.com\/","appurl":"http:\/\/noter2.dbelement.com"},{"id":"3","name":"Noter 2","description":null,"icon":"http:\/\/images.apple.com\/webapps\/productivity\/images\/noter2_20091223182720-thumb.jpg","date":"1262032317","company":"dBelement, LLC","companyurl":"http:\/\/dbelement.com\/","appurl":"http:\/\/noter2.dbelement.com"}]解决方案:
可能的原因是使用非 UTF8 编码检索数据。要解决此问题，请在 SELECT 查询之前添加以下行：
mysql_query('SET CHARACTER SET utf8');这将确保以 UTF8 编码检索数据，这将允许 json_encode 正确编码“描述”字段。
以上是为什么我的'json_encode”函数在 PHP JSON 响应中的描述字段返回 NULL？的详细内容。更多信息请关注PHP中文网其他相关文章！
