现有的PHP代码输出XML节点时,只能输出第一个同名节点内容"100". 请问怎样才能输出所有节点的内容呢?
现有代码见下:
/* $xmlstring 原内容:
**
-
*/
$xmldoc = new DOMDocument();
$xmldoc->loadXML($xmlstring);
$users = $xmldoc->getElementsByTagName('GetUserInfo');
foreach ($users as $user) {
$html .= 'outputCustomer:'.get_txt($user,'Customer').'
';
$html .= 'outputGeo:'.get_txt($user,'GeocallCLI').'
';
}
echo $html;
function get_txt($parent, $name) {
$nodes = $parent->getElementsByTagName($name);
return $nodes->item(0)->nodeValue;
}
?>
现有的PHP代码输出XML节点时,只能输出第一个同名节点内容"100". 请问怎样才能输出所有节点的内容呢?
现有代码见下:
/* $xmlstring 原内容:
**
-
*/
$xmldoc = new DOMDocument();
$xmldoc->loadXML($xmlstring);
$users = $xmldoc->getElementsByTagName('GetUserInfo');
foreach ($users as $user) {
$html .= 'outputCustomer:'.get_txt($user,'Customer').'
';
$html .= 'outputGeo:'.get_txt($user,'GeocallCLI').'
';
}
echo $html;
function get_txt($parent, $name) {
$nodes = $parent->getElementsByTagName($name);
return $nodes->item(0)->nodeValue;
}
?>
最后一行代码
<code>return $nodes->item(0)->nodeValue;</code>
因为只返回item(0)
所以只看得到一个100
只需检测$nodes的长度,循环输出即可
代码
<code><?php $xmlstring = '<?xml version="1.0"?> <!DOCTYPE GetUserInfo> <GetUserInfo> <Customer>id*cn</Customer> <GeocallCLI>100</GeocallCLI> <GeocallCLI>101</GeocallCLI> <GeocallCLI>102</GeocallCLI> <GeocallCLI>103</GeocallCLI> <GeocallCLI>105</GeocallCLI> </GetUserInfo>'; $xmldoc = new DOMDocument(); $xmldoc->loadXML($xmlstring); $users = $xmldoc->getElementsByTagName('GetUserInfo'); $html = ''; foreach ($users as $user) { $html .= get_txt($user, 'Customer') . ' '; $html .= get_txt($user, 'GeocallCLI') . ' '; } echo $html; function get_txt($parent, $name) { $nodes = $parent->getElementsByTagName($name); $data = ''; for ($i = 0; $i < $nodes->length; $i++) { $data .= 'output' . $name . ':' . $nodes->item($i)->nodeValue . '<br/>'; } return $data; } ?></code>
可否代码示例,谢谢!