class Foo {
#one
#two
#three
#four
#five
#six
#seven
#eight
#nine
#ten
#eleven
#twelve
#thirteen
#fourteen
#fifteen
#sixteen
constructor(
one,
two,
three,
four,
five,
six,
seven,
eight,
nine,
ten,
eleven,
twelve,
thirteen,
fourteen,
fifteen,
sixteen
) {
this.#one = one;
this.#two = two;
this.#three = three;
this.#four = four;
this.#five = five;
this.#six = six;
this.#seven = seven;
this.#eight = eight;
this.#nine = nine;
this.#ten = ten;
this.#eleven = eleven;
this.#twelve = twelve;
this.#thirteen = thirteen;
this.#fourteen = fourteen;
this.#fifteen = fifteen;
this.#sixteen = sixteen;
}
}
這個（反？）模式的解決方案是什麼？
對於任何想要使用建構函數的人來說，擁有 16 個參數並不有趣。您在評論中提出的配置對像想法要有趣得多，當然，當您將其與擁有具有所有這些屬性的類型對象的私有屬性的想法結合起來時。然後您可以使用
Object.assign來根據使用者的首選項更新它：class Foo { #options = { one: 1, two: 2, three: 3, four: 4 } constructor(options = {}) { Object.assign(this.#options, options); console.log(this.#options); } } let foo = new Foo({three: 3000});