我有 4 個 MySQL 表，使用 PHP 和 Laravel 7
現在我想連續顯示每個會員的單筆付款和所有其他扣除額。 （假設一個人只有一筆付款）
資料庫架構如下
這是我要顯示的 HTML 表格
這是我正在使用的查詢，但它重複了資料。
$payments = Payment::leftJoin('members', 'payments.member_id', '=', 'members.id')
->leftJoin('payment_deductions', 'payments.id', '=', 'payment_deductions.payment_id')
->leftJoin('deductions', 'payment_deductions.deduction_id', '=', 'deductions.id')
->select(
'members.*',
'payment_deductions.*',
)
->orderBy("member_id", "ASC")
->get()->toArray();
結果陣列根據每個成員的推導重複每個成員。
有什麼辦法可以更好地取得這些數據嗎？類似於每個成員的嵌套扣除數組？
這是模型
會員
namespace App;
use IlluminateDatabaseEloquentModel;
use CarbonCarbon;
class Member extends Model
{
protected $fillable = [
'full_name',
'email',
'created_by',
];
}
付款
namespace App;
use IlluminateDatabaseEloquentModel;
class Payment extends Model
{
protected $fillable = [
'member_id',
'total_amount',
'payable_amount',
'created_by',
];
public function deductions() {
return $this->belongsToMany(Deduction::class,'payment_deductions')->withTimestamps();
}
}
扣除
namespace App;
use IlluminateDatabaseEloquentModel;
class Deduction extends Model
{
protected $fillable = [
'title',
'priority',
'created_by',
];
}
在建立模型時，您非常接近並且處於正確的軌道上，您缺少的是如何在不創建另一個查詢的情況下加載關係，如果您查看控制器，您將看到加載內部關係的標準方法。希望這是一個更好的概念來解決您的擔憂。
供參考：https://laravel.com/ docs/9.x/eloquent-relationships#lazy-eager-loading
這樣做也可以避免未來的
N 1問題，請參閱什麼是 ORM（物件關係映射）中的「N 1 選擇問題」？ 有關N 1的詳細資訊會員模型
public class Member extends Model { protected $fillable = [ 'full_name', 'email', 'created_by', ]; public function payments(){ return $this->hasMany(Payment::class); } }支付模式
public class Payment extends Model { protected $fillable = [ 'member_id', 'total_amount', 'payable_amount', 'created_by', ]; public function member(){ return $this->belongsTo(Member::class); } public function deductions() { return $this->belongsToMany(Deduction::class,'payment_deductions')->withTimestamps(); } }推演模型
#public class Deduction extends Model { protected $fillable = [ 'title', 'priority', 'created_by', ]; public function payments() { return $this->belongsToMany(Payment::class,'payment_deductions')->withTimestamps(); } }成員控制器：
#/** * Show the specified model. * * @param \Illuminate\Http\Request $request * @param Member $member * @return \Illuminate\Http\Response */ public function show(Request $request, Member $member){ // This will load all of the inner relationships in a single query. $member->load('payments.deductions'); //Assign the loaded payments to be used $payments = $member->payments; /* You can acess the payments -> deductions in a foreach loop, in php or blade foreach($payments->deductions as $deduction){ //$deduction->id } */ return view('sampleView', compact('member', 'payments')); }