我無法理解為什麼IndexOf返回了-1
P粉031492081
P粉031492081 2023-09-14 20:02:21
0
1
577

我有一個包含1-20的數字數組。當我使用indexOf方法嘗試找到"2"的位置時,它顯示在第3個位置(正確)。

我有一個名為day = 2的變數。當我使用array.indexOf(day)的程式碼時,它會傳回-1

為什麼會發生這種情況?

P粉031492081
P粉031492081

全部回覆(1)
P粉517090748
function indexofnotworking() {
  let arr = [...new Array(20).keys()];//creat arr of numbers from 0  -19
  let arr1 = arr.slice().reverse();//make a copy and reverse it
  [...Array.from(new Array(5).keys(), x => x + 5)].forEach(n => {
    console.log('arr: %s n: %s index: %s', JSON.stringify(arr), n, arr.indexOf(n));//find the indexof n in both arrays
    console.log('arr1: %s n: %s index: %s', JSON.stringify(arr1), n, arr1.indexOf(n));/display results
  })
}

11:40:22 AM Info    arr: [0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19] n: 5 index: 5
11:40:22 AM Info    arr1: [19,18,17,16,15,14,13,12,11,10,9,8,7,6,5,4,3,2,1,0] n: 5 index: 14
11:40:22 AM Info    arr: [0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19] n: 6 index: 6
11:40:22 AM Info    arr1: [19,18,17,16,15,14,13,12,11,10,9,8,7,6,5,4,3,2,1,0] n: 6 index: 13
11:40:22 AM Info    arr: [0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19] n: 7 index: 7
11:40:22 AM Info    arr1: [19,18,17,16,15,14,13,12,11,10,9,8,7,6,5,4,3,2,1,0] n: 7 index: 12
11:40:22 AM Info    arr: [0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19] n: 8 index: 8
11:40:22 AM Info    arr1: [19,18,17,16,15,14,13,12,11,10,9,8,7,6,5,4,3,2,1,0] n: 8 index: 11
11:40:22 AM Info    arr: [0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19] n: 9 index: 9
11:40:22 AM Info    arr1: [19,18,17,16,15,14,13,12,11,10,9,8,7,6,5,4,3,2,1,0] n: 9 index: 10
熱門教學
更多>
最新下載
更多>
網站特效
網站源碼
網站素材
前端模板
關於我們 免責聲明 Sitemap
PHP中文網:公益線上PHP培訓,幫助PHP學習者快速成長!