我別無選擇，只能在處理程序中呼叫獲取器的提交方法。它正在存取路由器中正確的操作方法，但是我無法將該方法傳遞給操作，即表單中定義的 method='POST 。如何存取處理程序內的fetch.Form方法？
const fetcher = useFetcher()
const handlerLogin = useCallback(async () => {
console.log(fetcher.formMethod) //-> outputting undefined
fetcher.submit({ value: 'social' }, { method: fetcher.formMethod })
},[])
return (
<Card className={styles.loginCard}>
<fetcher.Form method='POST' action='/'>
.............. 
嘗試這個解決方案，將方法傳遞給
handlerLogin函數：const fetcher = useFetcher(); const handlerLogin = useCallback(async (formMethod) => { fetcher.submit({ value: 'social' }, { method: formMethod }); }, []); return ( <Card className={styles.loginCard}> <fetcher.Form method='POST' action='/' > {/* other parts ... */} <button onClick={() => handlerLogin(fetcher.formMethod)}> Submit </button> </fetcher.Form> </Card> );