第二次使用相同檔案名稱的圖片，進行上傳時提示檔案已存在，路徑也儲存不了資料庫，檔案名稱也無法存入資料庫，導致不顯示。 ，請教大神在哪裡加程式碼處理這個問題？

第二個問題，在哪裡加程式碼壓縮圖片檔案大小

<?phpif (count($_FILES)) {    $retFiles = uploadFile("file");    if ($ retFiles['status'] == 1) {        echo $retFiles['message'];    } else if ($retFiles['status'] == 0) {        echo "Upload: "name. $== 0) {        echo "Upload: "name. $ret. "<br />";        echo "Type: " .  $retFiles["type"] . "<br />";        echo "Size: " . ($retFiles["size" / 1024) . " Kb<br />";        echo "Temp file: " . $retFiles["temp"] . "<br />";        echo "Stored in: " . "../upload/" . $    echo "Stored in: " . "../upload/" . $./uploadFiles ["name"];    }}
function uploadFile($fileName){ $files = $_FILES[$fileName];    if (!in_array($files["type"], array("image/gif"," image/jpeg","image/pjpeg","image/jpeg", "image/png"))) {        return array("status" => 1, "message" => "Uploaded image format is not correct ");    }        if ($files["error"] > 0) {        return array("status" => 1, "message" => "upload error"); upload/" . $files["name"])) {        return array("status" => 1, "message" => $files["name"]." already exiss")); ['file']['tmp_name'], '../upload/'.iconv("UTF-8", "gbk",$_FILES['file']['name']));    return array(" status" => 0, "name" => $files["name"], "type" => $files["type"], "size" => $files['size']/1024 , "temp" => $files["tmp_name"]); }