python如何轉換時間戳到"2017年6月12日 18點24分"這樣的格式呢?謝謝
import time
timestamp = time.time()
time.strftime('%Y年%m月%d日 %H时%M分', time.localtime(timestamp))
Traceback (most recent call last):
File "<input>", line 1, in <module>
UnicodeEncodeError: 'locale' codec can't encode character '\u5e74' in position 2: Illegal byte sequence
另外吐槽下,chrome下開啟segmentfault顯示記憶體用完崩潰的錯誤到底什麼時候修啊啊啊啊啊啊!
雷雷
還真被我研究出來種萬能方法,據我百度Google貌似這還是世上獨一份?
話不多說,下面上解決原理及方案:
官方文件:https://docs.python.org/3/lib...
class
time.
`struct_time`¶The type of the time value sequence returned by
. It is an object with a named tupled 4000m. The following values are present:gmtime()
,localtime()
, andstrptime()
. It is an object with a named tupleptime()tm_year
tm_mon
tm_mday
tm_hour
tm_min
tm_sec
in
strftime()tm_wday
tm_yday
tm_isdst
tm_zone
tm_gmtoff
Note that unlike the C structure, the month value is a range of [1, 12], not [0, 11].
In calls to
mktime(),
tm_isdst y is is in effect, and 0 when it is not. A value of -1 indicates that this is not known, and will usually result in the correct state being filled in.When a tuple with an incorrect state being filled in.
When a tuple with an incorrect state being filled in.
When a tuple with an incorrect length is passrrectstruct_time
, or having elements of the wrong type, ais raised.
看文件可以得知time.localtime()回傳的元組結構,我要用到的是年月日時分,前5個,於是乎,程式碼:
輸出:
搞定。
🎜轉載請註明出處,謝謝。 🎜