PHP 一個多維數組排序的問題
滿天的星座
滿天的星座 2017-05-16 13:08:20
0
9
540

這個問題有點類似 Mysql 中 order by ,需要的就是在陣列中模擬不同欄位的排序。

假如有以下數組:

$beforeSort = [ "0" => ["name" => "张三", "english" => 80, "chinese" => 60, "math" => 50 ], "1" => ["name" => "李四", "english" => 50, "chinese" => 60, "math" => 70 ], "2" => ["name" => "老王", "english" => 30, "chinese" => 50, "math" => 80 ], ];

現在需要在數組中按照chinese順序,假如有相同,就按math順序,最後得到的應該是如下的數組:

$afterSort = [ "2" => ["name" => "老王", "english" => 30, "chinese" => 50, "math" => 80 ], "0" => ["name" => "张三", "english" => 80, "chinese" => 60, "math" => 50 ], "1" => ["name" => "李四", "english" => 50, "chinese" => 60, "math" => 70 ], ];

請問大家有什麼不同的方法可以實現?

滿天的星座
滿天的星座

全部回覆 (9)
左手右手慢动作

這是我自己使用的版本,使用方法:

$afterSort = getArraySort($beforeSort, 'chinese', 'SORT_ASC', 'math', 'SORT_ASC');
/** * 二维数组排序(数字索引数组将重建索引) * @param array $arr 需要排序的数组 二维数组 * @param string $arg1 排序的键名或字段名 * @param string $arg2 排序的顺序 SORT_ASC或SORT_DESC * @param string $arg3 排序的方法 SORT_REGULAR * @return array */ function getArraySort($arr, $arg1, $arg2 = "SORT_ASC", $arg3 = "SORT_REGULAR") { if (!is_array($arr) || !$arr) { return $arr; } $argcount = func_num_args(); for ($i = 1; $i < $argcount; $i++) { $arg = func_get_arg($i); if (!preg_match("/SORT_(.*)/i", $arg)) { $keynamelist[] = $arg; $sortrule[] = '$' . $arg; } else { $sortrule[] = $arg; } } foreach ($arr AS $key => $info) { foreach ($keynamelist AS $keyname) { ${$keyname}[$key] = $info[$keyname]; } } $evalstring = 'array_multisort(' . join(",", $sortrule) . ',$arr);'; eval($evalstring); return $arr; }
    迷茫
    $beforeSort = [ "0" => ["name" => "张三", "english" => 80, "chinese" => 60, "math" => 50 ], "1" => ["name" => "李四", "english" => 50, "chinese" => 60, "math" => 70 ], "2" => ["name" => "老王", "english" => 30, "chinese" => 50, "math" => 80 ], ]; $arr = array(); foreach($beforeSort as $value) { $arr[$value['chinese']][$value['math']] = $value; } sort($arr); $result = array(); foreach($arr as $val) { sort($val); foreach($val as $vo) { $result[] = $vo; } } var_dump($result);die;

    列印結果:

    array(3) { [0]=> array(4) { ["name"]=> string(6) "老王" ["english"]=> int(30) ["chinese"]=> int(50) ["math"]=> int(80) } [1]=> array(4) { ["name"]=> string(6) "张三" ["english"]=> int(80) ["chinese"]=> int(60) ["math"]=> int(50) } [2]=> array(4) { ["name"]=> string(6) "李四" ["english"]=> int(50) ["chinese"]=> int(60) ["math"]=> int(70) } }
      大家讲道理

      可以將數組轉為集合,再處理。使用php的集合實現的sort方法,專治各種複雜排序

        PHPzhong

        //現在需要在數組中按照 chinese 順序,假如有相同,就按 math 順序,最後得到的應該是如下的數組:
        $beforeSort = [

        "0" => ["name" => "张三", "english" => 80, "chinese" => 60, "math" => 50 ], "1" => ["name" => "李四", "english" => 50, "chinese" => 60, "math" => 70 ], "2" => ["name" => "老王", "english" => 30, "chinese" => 50, "math" => 80 ],

        ];

        $data_math = array_column($beforeSort,'math');
        $data_chinese = array_column($beforeSort,'chinese');
        ,$datasultisort($data_chinese,SOSO_Scfore_multisort" ort );

          我想大声告诉你

          雷雷

            大家讲道理

            ///借用樓上哥們答案

            usort($beforeSort, function ($a, $b) { return [$a['chinese'], $b['math']] <=> [$b['chinese'], $a['math']]; });
              某草草

              對多維數組排序,官方有一個函數可以實作 array_multisort

                伊谢尔伦

                雷雷

                  Peter_Zhu

                  $排序前 = [

                  雷雷

                  ];

                  foreach ($beforeSort as $key => $value) {

                  雷雷

                  }
                  array_multisort($chinese, SORT_ASC, $math, SORT_ASC, $beforeSort);
                  print_r($beforeSort);

                    最新下載
                    更多>
                    網站特效
                    網站源碼
                    網站素材
                    前端模板
                    關於我們 免責聲明 Sitemap
                    PHP中文網:公益線上PHP培訓,幫助PHP學習者快速成長!