給定了天數，任務是將給定的天數轉換為年、週和天。
讓我們假設一年中的天數=365
年數=（天數）/365
解釋-：年數將是除以給定天數得到的商與365
週數= (天數% 365) / 7
解釋-：週數將透過收集餘數獲得將天數除以365 ，再除以一週的天數7。
天數= (天數% 365) % 7
說明-：天數是用天數除以365所得的餘數再除以一週的天數7所得的餘數。
Input-:days = 209 Output-: years = 0 weeks = 29 days = 6 Input-: days = 1000 Output-: years = 2 weeks = 38 days = 4
Start
Step 1-> declare macro for number of days as const int n=7
Step 2-> Declare function to convert number of days in terms of Years, Weeks and Days
void find(int total_days)
declare variables as int year, weeks, days
Set year = total_days / 365
Set weeks = (total_days % 365) / n
Set days = (total_days % 365) % n
Print year, weeks and days
Step 3-> in main()
Declare int Total_days = 209
Call find(Total_days)
Stop現場示範
#include <stdio.h>
const int n=7 ;
//find year, week, days
void find(int total_days) {
int year, weeks, days;
// assuming its not a leap year
year = total_days / 365;
weeks = (total_days % 365) / n;
days = (total_days % 365) % n;
printf("years = %d",year);
printf("</p><p>weeks = %d", weeks);
printf("</p><p>days = %d ",days);
}
int main() {
int Total_days = 209;
find(Total_days);
return 0;
}如果我們執行上述程式碼，它將產生以下輸出
years = 0 weeks = 29 days = 6
以上是寫一個C程序，將給定的天數轉換為年、週和天的詳細內容。更多資訊請關注PHP中文網其他相關文章！
