php怎麼輸出彈跳窗錯誤提示

error_reporting(E_ALL);
function cache_shutdown_error() {
          $_error = error_get_last();
          if ($_error && in_array($_error['type'], array(1, 4, 16, 64, 256, 4096, E_ALL)))
{
                    header("Content-Type: text/html; charset=utf-8");
                    echo &#39;<font color=red>你的代码出错了：</font></br>&#39;;
                    echo &#39;致命错误:&#39; . $_error[&#39;message&#39;] . &#39;</br>&#39;;
                    echo &#39;文件:&#39; . $_error[&#39;file&#39;] . &#39;</br>&#39;;
                    echo &#39;在第&#39; . $_error[&#39;line&#39;] . &#39;行</br>&#39;;
                }
            }
 register_shutdown_function("cache_shutdown_error");