java怎麼判斷字串是否整數

public static boolean isNumeric(String str){
  for (int i = 0; i < str.length(); i++){
   System.out.println(str.charAt(i));
   if (!Character.isDigit(str.charAt(i))){
    return false;
   }
  }
  return true;
 }

public boolean isNumeric(String str){ 
   Pattern pattern = Pattern.compile("[0-9]*"); 
   Matcher isNum = pattern.matcher(str);
   if( !isNum.matches() ){
       return false; 
   } 
   return true; 
}

org.apache.commons.lang.StringUtils;
boolean isNunicodeDigits=StringUtils.isNumeric("aaa123456789");
下面的解释:
isNumeric
public static boolean isNumeric(String str)Checks if the String contains only unicode digits. A decimal point is not a unicode digit and returns false.
null will return false. An empty String ("") will return true.
 StringUtils.isNumeric(null)   = false
 StringUtils.isNumeric("")     = true
 StringUtils.isNumeric("  ")   = false
 StringUtils.isNumeric("123")  = true
 StringUtils.isNumeric("12 3") = false
 StringUtils.isNumeric("ab2c") = false
 StringUtils.isNumeric("12-3") = false
 StringUtils.isNumeric("12.3") = false
 
Parameters:
str - the String to check, may be null 
Returns:
true if only contains digits, and is non-null