一、什麼是JSON
JSON是一種輕量級的資料交換格式，採用完全獨立於程式語言的文字格式來儲存和表示資料。簡潔和清晰的層次結構使得 JSON 成為理想的資料交換語言。易於閱讀和編寫，同時也易於解析和生成，並有效地提升網路傳輸效率。
二、JSON 語法
（1）資料在名稱/值對中
（2）資料以逗號分隔
#（3）大括號保存物件 （4）中括號保存陣列三、Java中JSON的產生與解析的四種方式(簡單的Demo)：一個實體類別：用於與JSON資料進行相互轉換
public class Person {
private String name;
private String sex;
private int age;
public Person(String name, String sex, int age) {
this.name = name;
this.sex = sex;
this.age = age;
}
public String getName() {
return name;
}
public String getSex() {
return sex;
}
public int getAge() {
return age;
}
@Override
public String toString() {
return "Person{name='" + name + '\'' + ", sex='" + sex + '\'' + ", age=" + age + '}';
}
}public Person getPerson(){
return new Person("张三", "男", 25);
}
@Test
public void EntityToJson(){
JSONObject jsonObject = new JSONObject();
jsonObject.put("name", getPerson().getName());
jsonObject.put("sex", getPerson().getSex());
jsonObject.put("age", getPerson().getAge());
System.out.println(jsonObject.toString());
}@Test
public void JsonToEntity(){
String jsonString = "{\"sex\":\"男\",\"name\":\"张三\",\"age\":25}";
JSONObject jsonObject = new JSONObject(jsonString);
Person person = new Person(jsonObject.get("name").toString(), jsonObject.get("sex").toString(), Integer.valueOf(jsonObject.get("age").toString()));
System.out.println(person.toString());
}@Test
public void EntityToJson() throws IOException {
Person person = new Person("张三", "男", 25);
ObjectMapper objectMapper = new ObjectMapper();
String jsonString = objectMapper.writeValueAsString(person);
System.out.println(jsonString);
}@Test
public void JsonToEntity() throws IOException {
ObjectMapper objectMapper = new ObjectMapper();
String jsonString = "{\"name\":\"张三\",\"sex\":\"男\",\"age\":25}";
Person person = objectMapper.readValue(jsonString, Person.class);
System.out.println(person);
}@Test
public void EntityToJson(){
Person person = new Person("张三", "男", 25);
Gson gson = new Gson();
String jsonString = gson.toJson(person);
System.out.println(jsonString);
}@Test
public void JsonToEntity(){
String jsonString = "{\"name\":\"张三\",\"sex\":\"男\",\"age\":25}";
Gson gson = new Gson();
Person person = gson.fromJson(jsonString, Person.class);
System.out.println(person.toString());
}
@Test
public void EntityToJson(){
Person person = new Person("张三", "男", 25);
Object jsonString = JSON.toJSON(person);
System.out.println(jsonString.toString());
}@Test
public void JsonToEntity(){
String jsonString = "{\"name\":\"张三\",\"sex\":\"男\",\"age\":25}";
Person person = JSON.parseObject(jsonString, Person.class);
System.out.println(person.toString());
}以上是JAVA的json怎麼解析的詳細內容。更多資訊請關注PHP中文網其他相關文章！
