p5.j​​s 畢達哥拉斯樹的實作程式碼

function Pythagorian(x){
 noStroke();
 fill(107, 142, 35,map(x, 0, a, 150, 255));//根据正方形边长设置填充色
 rect(0,0,x,x);//绘制当前的正方形
 
 if(x <= 3) return 0;//当正方形边长小于3时，结束递归

 /* 绘制右上角的正方形 */ 
 push();
 rotate(PI / 2 - t);//坐标轴顺时针旋转约37deg
 translate(0,-x/5 * 3 - x/5*4);//坐标轴向上平移3边+4边的长度
 Pythagorian(x/5*4);//递归调用毕达哥拉斯函数
 pop();
 
 /* 绘制左上角的正方形 */
 push();
 rotate( - t);//坐标轴逆时针旋转约53deg
 translate(0,-x/5 * 3);//坐标轴向上平移3边的长度
 Pythagorian(x/5*3);//递归调用毕达哥拉斯函数
 pop(); 
 
}

var a = 100; //最大正方形边长
var t;//4边所对应的角度
function setup(){
 t = 53.1301024 / 360 * 2 * PI;//约为53deg
 createCanvas(windowWidth, windowHeight);//创建画布
 background(255);
 noLoop();//draw()函数只执行一次
}

function draw(){
 translate(windowWidth/2, windowHeight - a * 2);//将坐标系平移至画布中间底部
 Pythagorian(a);//调用毕达哥拉斯递归函数
}

var a = 100;
var t;
function setup(){
 t = 53.1301024 / 360 * 2 * PI;
 createCanvas(windowWidth, windowHeight);
 background(255);
 noLoop();
}
function draw(){
 translate(windowWidth/2, windowHeight - a * 2);
 Pythagorian(a);
 
}
function Pythagorian(x){
 noStroke();
 fill(107, 142, 35,map(x, 0, a, 150, 255));
 rect(0,0,x,x);
 
 if(x <= 3) return 0;
 
 push();
 rotate(PI / 2 - t);
 translate(0,-x/5 * 3 - x/5*4);
 Pythagorian(x/5*4);
 pop();
 
 push();
 rotate( - t);
 translate(0,-x/5 * 3);
 Pythagorian(x/5*3);
 pop(); 
 
}