<code>var xx = 'dfdf';
var yy = 'kfdl';
var zz = 'ijklk';
instance:[{"instance_name":xx,"machine_belong":yy,"access_port":zz},{"instance_name":xx,"machine_belong":yy,"access_port":zz}]
</code>php後台如何處理
instance = [{"instance_name":1,"machine_belong":2,"access_port":3},{"instance_name":1,"machine_belong":2,"access_port":3}];
用這個做了測試,是json寫的不對，我代碼裡json是拼接的,拼接有錯誤
![[已解決]php如何解析這樣的json字串](/img/bVD1Ae?w=657&h=132)
<code>var xx = 'dfdf';
var yy = 'kfdl';
var zz = 'ijklk';
instance:[{"instance_name":xx,"machine_belong":yy,"access_port":zz},{"instance_name":xx,"machine_belong":yy,"access_port":zz}]
</code>php後台如何處理
instance = [{"instance_name":1,"machine_belong":2,"access_port":3},{"instance_name":1,"machine_belong":2,"access_port":3}];
用這個做了測試,是json寫的不對，我代碼裡json是拼接的,拼接有錯誤
<code>instance = [{"instance_name":xx,"machine_belong":yy,"access_port":zz},{"instance_name":xx,"machine_belong":yy,"access_port":zz}]
// 对instance json序列化, 才可以进行数据传输
instance = JSON.stringify(instance);</code>PHP解析:
<code>$instance = json_decode($_REQUEST['instance'], true);</code>
不謝
你應該把物件先轉成 字符串符號 ，然後再發送給後台
看到你的程式碼，是js發往php介面？
如果是這樣，用post，php可以用$res=$_post['data']
假如你的呼叫介面是以，ajax({data:{...}});
接下來，php的取得對象，類似res.name
https://github.com/yiisoft/yi...
請參考這個程式碼
http://json.cn/ 測驗json格式
