javascript - 一個計算每一幀旋轉度數的演算法

<code>var a = 0.01;
var totalDeg = 360;
var steps = [];

function countSteps() {
    var t = Math.sqrt(2 * totalDeg / a);
    var v = a * t;
    for (var i = 0; i < t; i++) {
        steps.push((2 * v * i - a * i * i) / 2)
    }
    steps.push(totalDeg)
}

</code>

<code>var a = 0.01;
var totalDeg = 360;
var steps = [];

function countSteps() {
    var t = Math.sqrt(2 * totalDeg / a);
    var v = a * t;
    for (var i = 0; i < t; i++) {
        steps.push((2 * v * i - a * i * i) / 2)
    }
    steps.push(totalDeg)
}

</code>