<code><script>
var images = document.getElementsByClassName("c1");
var imageStr = "";
for(var i=0;i<images.length;i++){
imageStr+=images[i].src+'_';
}
alert(imageStr);
</script>
</code>如何設定一個按鈕，點選後post imageStr裡面的陣列到PHP
<code>$imageStr = "http://127.0.0.1/down/123.gif__http://127.0.0.1/down/8095680852_893f685cbd_q.jpg__http://127.0.0.1/down/8018953043_c6ef9e3b29_q.jpg__"; </code>
提問前請先搜尋相關答案:
https://segmentfault.com/sear...
<code><script>
var images = document.getElementsByClassName("c1");
var imageStr = "";
for(var i=0;i<images.length;i++){
imageStr+=images[i].src+'_';
}
alert(imageStr);
</script>
</code>如何設定一個按鈕，點選後post imageStr裡面的陣列到PHP
<code>$imageStr = "http://127.0.0.1/down/123.gif__http://127.0.0.1/down/8095680852_893f685cbd_q.jpg__http://127.0.0.1/down/8018953043_c6ef9e3b29_q.jpg__"; </code>
提問前請先搜尋相關答案:
https://segmentfault.com/sear...
範例
<code>$( "#lock_submit").click(function (){
var lock_form = $("#lock_form").serialize(); // 参数带在form里面用form表单
var onePush = "xxx/xxx/xxx.php" ;
var imageStr ="http://127.0.0.1/down/123.gif__http://127.0.0.1/down/8095680852_893f685cbd_q.jpg__http://127.0.0.1/down/8018953043_c6ef9e3b29_q.jpg__";
$.ajax({
url: onePush ,
type:"POST",
data：{image:imageStr},//data:lock_form form提交
dataType : "json",
success :function(data){
if(data.status== 1){
alert('操作成功')
// 刷选页面
location. reload();
}else{
alert('操作失败')
}
}
})
})
</code>
表單提交就可以了
$.post(url,{imageStr:$imageStr},function(res){
<code>//do somethings </code>
})
