如何在不使用正規表示式的情況下刪除 JavaScript 中的查詢字串參數？

function removeURLParameter(url, parameter) {
    // Parse the URL into parts
    var urlparts = url.split('?');

    // If there's no query string, return the original URL
    if (urlparts.length < 2) {
        return url;
    }

    // Split the query string into individual parameters
    var pars = urlparts[1].split(/[&;]/g);

    // Reverse iterate to ensure the order of items after splicing
    for (var i = pars.length; i--;) {
        // Check if the parameter starts with the specified prefix
        if (pars[i].lastIndexOf(encodeURIComponent(parameter) + '=', 0) !== -1) {
            // Remove the offending parameter
            pars.splice(i, 1);
        }
    }

    // Rebuild the query string
    var newQuery = (pars.length > 0 ? '?' + pars.join('&') : '');

    // Rebuild the full URL
    return urlparts[0] + newQuery;
}