方法一
echo strtotime('last Monday');
echo '
';
echo strtotime('next Sunday');
?>
方法二
02 function getMonSun(){
03 $curTime=time();
04
05 $curWeekday = date('w');
06
07 //为0是 就是 星期七
08 $curWeekday = $curWeekday?$curWeekday:7;
09
10
11 $curMon = $curTime - ($curWeekday-1)*86400;
12 $curSun = $curTime + (7 - $curWeekday)*86400;
13
14 $cur['Mon'] = $curMon;
15 $cur['Sun'] = $curSun;
16
17 return $cur;
18 }
19 $cur = getMonSun();
20
21 echo date('Y-m-d',$cur['Mon']);
22 echo "rn";
23 echo date('Y-m-d',$cur['Sun']);
24 ?>
方法三
02 function getMonSun(){
03 $curTime=time();
04
05 //求出当前是星期几：
06 $curWeekday = date('w');
07
08 //如果是周一则减上7*86400周二减上6*86400，依此类推得到周一的时间戳：
09 switch ($curWeekday) {
10 case 0:
11 $curMon = $curTime-7*86400;
12 $curSun = $curTime;
13 break;
14 case 1:
15 $curMon = $curTime;
16 $curSun = $curTime+6*86400;
17 break;
18 case 2:
19 $curMon = $curTime-1*86400;
20 $curSun = $curTime+5*86400;
21 break;
22 case 3:
23 $curMon = $curTime-2*86400;
24 $curSun = $curTime+4*86400;
25 break;
26 case 4:
27 $curMon = $curTime-3*86400;
28 $curSun = $curTime+3*86400;
29 break;
30 case 5:
31 $curMon = $curTime-4*86400;
32 $curSun = $curTime+2*86400;
33 break;
34 case 6:
35 $curMon = $curTime-5*86400;
36 $curSun = $curTime+1*86400;
37 break;
38 }
39 $cur['Mon'] = $curMon;
40 $cur['Sun'] = $curSun;
41
42 return $cur;
43 }
44 $cur = getMonSun();
45 echo date('Y-m-d',$cur['Mon']);
46 echo "rn";
47 echo date('Y-m-d',$cur['Sun']);
48 ?>
