/** * @create on 17/3/27 * @description */ public class Main { static volatile int i = 0; public static class PlusTask implements Runnable{ @Override public void run(){ for(int k=0; k<10000; k++) i++; } } public static void main(String[] args) throws InterruptedException{ Thread[] threads = new Thread[10]; for(int i=0;i<10;i++){ threads[i] = new Thread(new PlusTask()); threads[i].start(); } for(int i=0;i<10;i++){ threads[i].join(); } System.out.println(i); } }请教各位大牛 为什么这里的输出总是小于10000？ 已经调用了thread.join
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You may need this:
or define one
AtomicIntegervolatile only functions as a multi-thread cache consistency, and does not guarantee that only one thread will write variables at a certain time.
volitile does not guarantee atomicity
The problem of multi-threaded operation of shared variables. Volitale cannot guarantee the atomicity of composite operations, which means that the latter thread cannot always see the modified value i of the previous thread. The solution is to lock or atomically operate