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response.doc('.link_nei>ul>li>a').items()上面的语句是用来获取所有符合条件的 ，我想获得倒数第二个 应该怎么获得？ 教程上都是通过正则表达式去筛选，不过这种方法好 low 而且不实用
人生最曼妙的风景，竟是内心的淡定与从容！
response.doc('.link_nei>ul>li>a').eq(-2).items()
Refer to the pyquery documentation https://pythonhosted.org/pyqu...
I see you are using a CSS selector, just add:nth-last-child(2)after a.
CSS selector tutorial: http://www.w3school.com.cn/cs...
![[Web front-end] Node.js quick start](https://img.php.cn/upload/course/000/000/067/662b5d34ba7c0227.png)
Refer to the pyquery documentation https://pythonhosted.org/pyqu...
I see you are using a CSS selector, just add:nth-last-child(2)after a.
CSS selector tutorial: http://www.w3school.com.cn/cs...