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计算 t1、t2 相差的时间分钟数，大于半分钟的四舍五入，代码如下，t2 比 t1 多了一天多，但计算出来的结果仍然是 2，请问我哪里算错了吗？
import datetime t1 = datetime.datetime(2017,3,4,8,49,0) t2 = datetime.datetime(2017,3,5,8,50,30) min =(t2 - t1).seconds/60 m = round(min) print(m)
学习是最好的投资！
(t2-t1).total_seconds()才是所有的秒数吧
(t2-t1).total_seconds()
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(t2-t1).total_seconds()才是所有的秒数吧
(t2-t1).total_seconds()