deal_way = list(soup.select('p.biaoqian_li').stripped_strings)
#
deal_ways = soup.select('p.biaoqian_li')
for deal_way in deal_ways:
x = list(deal_way.stripped_strings)
上面两个代码不是表示同样的意思吗？
（1）为什么上面报错：AttributeError: 'list' object has no attribute 'stripped_strings'
（2）下面的可以运行
![[Web front-end] Node.js quick start](https://img.php.cn/upload/course/000/000/067/662b5d34ba7c0227.png)
Yes
soup.select()返回的是什么不是很清楚，但是看你下面的代码soup.select('p.biaoqian_li')returns a collection. Only the items in the collection have the stripped_strings attribute, not the collection.The two pieces of code are different
Obviously the code below uses one more
forthan the above codeYou can print
soup.select('p.biaoqian_li')andsoup.select('p.biaoqian_li')与for中的deal_wayindeal_wayCompare the differences
I’m really sorry, I didn’t make it clear at the beginning
It’s because I made a mistake in writing the code, so I keep reporting errors. It’s written as:
Thank you everyone