-(void)updateSearchResultsForSearchController:(UISearchController *)searchController {
NSString *searchString = [self.searchController.searchBar text];
if (searchString.length == 0) {
return;
}
NSPredicate *preicate = [NSPredicate predicateWithFormat:@"SELF CONTAINS[c] %@", searchString];
if (self.searchResult!= nil) {
[self.searchResult removeAllObjects];
}
//过滤数据
self.searchResult= [NSMutableArray arrayWithArray:[self.datasource filteredArrayUsingPredicate:preicate]];
//刷新表格
[self.tableView reloadData];
}
看例子的的排序都是对简单的字符串数组进行的筛选排序,对于字符串里是对象,按对象里的某个字符串进行筛选,这个可以做到吗?如果不能做到,那么一般用什么办法?以前都是直接用SQL来做的,这次需求里没用这个,能否直接在内容里进行这个
That is to say, the array contains model objects, and then matches the string of a certain attribute in the model object?
Match models with a character in the name field in the model
NSPredicate pre = [NSPredicate predicateWithFormat:@"name LIKE 'a*'"];
Supporting KVC is enough. If a single object in the Array is a Person, to check whether the name is included, use @"SELF.name CONTAINS[c] %@"