python - 为一个变量设置代理

Question

由于sae上不能使用flask-login,所以我只能自己写一个flask-login里的current_user 现在有一个函数get_current_user调用后会返回一个User对象如: {代码...} 怎么样给变量current_user设置一个代理使每一次调用这个...

巴扎黑 · Answer

The simplest way is to write a proxy class

def User(object):
    def function1(self):
        #some code

    def function2(self):
        #some code

class UserProxy(User):
    def function1(self):
        return get_current_user().function1()

    def function1(self):
        return get_current_user().function1()

current_user = UserProxy()

天蓬老师 · Answer

If that’s the case, are you willing? (Use random just for testing, you can ignore it...)

import random

class Current:

    @property
    def user(self):
        return random.randint(1, 10)

current = Current()
print(current.user)
print(current.user)
print(current.user)
print(current.user)

current.user 跟 current_user The number of words to type is the same

Result:

I think

There is nothing wrong with calling function...
But if there is an expert who knows how to do this (without using the object trick), please tell me!!

Questions I answered: Python-QA

阿神 · Answer

flask_login Isn’t it already done?

@login_manager.user_loader
def load_user(user_id):
    return User.get(user_id)

After setting it like this, each time current_user is called, the user object of the current user will be returned. Of course, User needs to implement the get_id() method.

Reference: flask_login

阿神 · Answer

from flask import session, redirect, url_for
from ..models import User
from werkzeug.local import LocalProxy
def get_current_user():
current_user = User.query.get(session.get('current_user_id'))
return current_user 
current_user = LocalProxy(get_current_user)

The current_user here is the current_user, LocalProxy agent has done it many times.