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假如我是 var s= "..........."
我的需求
将 标签内的内容替换成 其他内容
从起始位置计算， 在整个字符串中的index 位置
ringa_lee
You can consider using regular expressions to process
String.prototype.indexOf()String.prototype.substring()String.prototype.replace()
The question owner can use the above method to solve the problem
1 Use regular expression2 Use index of
s.replace(/]+)>/g, "新字符串")
![](\"/assets/emoji/smirk.png\")
....."
![[Web front-end] Node.js quick start](https://img.php.cn/upload/course/000/000/067/662b5d34ba7c0227.png)
You can consider using regular expressions to process
String.prototype.indexOf()
String.prototype.substring()
String.prototype.replace()
The question owner can use the above method to solve the problem
1 Use regular expression
2 Use index of