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我在尝试写个命令行的fm，但是碰到播放时间的适合遇到了问题，如何实现一个计时器，每次自减1秒后覆盖之前的print 输出我想把歌曲总时间传入如下代码，封装个函数，但是如何覆盖上一次print的结果呢？
def remain(min) count = 0 while (count < min): count += 1 n = min - count time.sleep(1) print n
学习是最好的投资！
先科普下，"\r" 表示光标回到行首(参考自ascii编码表)。利用它就能达到覆盖字符的效果，但前提是别换行（消灭\n）。来吧~ 看吾主的神迹。
pythonline = "=============================" print(line + "\r" + line, end='');print("\r" + line + "\r" + line)
python
line = "=============================" print(line + "\r" + line, end='');print("\r" + line + "\r" + line)
再补充个进度条demo
pythonimport time lineLength = 20 delaySeconds = 0.05 frontSymbol = '=' frontSymbol2 = ['—', '\\', '|', '/'] backSymbol = ' ' for i in range(10): lineTmpla = "{:%s<%s} {} {:<2}"%(backSymbol, lineLength) for j in range(lineLength): tmpSymbol = frontSymbol2[j%(len(frontSymbol2))] print("\r" + lineTmpla.format(frontSymbol * j, tmpSymbol, j), end='') time.sleep(delaySeconds)
import time lineLength = 20 delaySeconds = 0.05 frontSymbol = '=' frontSymbol2 = ['—', '\\', '|', '/'] backSymbol = ' ' for i in range(10): lineTmpla = "{:%s<%s} {} {:<2}"%(backSymbol, lineLength) for j in range(lineLength): tmpSymbol = frontSymbol2[j%(len(frontSymbol2))] print("\r" + lineTmpla.format(frontSymbol * j, tmpSymbol, j), end='') time.sleep(delaySeconds)
![[Web front-end] Node.js quick start](https://img.php.cn/upload/course/000/000/067/662b5d34ba7c0227.png)
先科普下，"\r" 表示光标回到行首(参考自ascii编码表)。利用它就能达到覆盖字符的效果，但前提是别换行（消灭\n）。
来吧~ 看吾主的神迹。
再补充个进度条demo