Because the elements between [hi,_size] are used to cover the elements in the [lo, _size+lo-hi] interval. hi increases to _size, and the corresponding lo will increase to _size+lo- hi, that is, _size+lo-hi is the position of the last element, that is, the new _size value
The code uses lo to mark the position of the last element, so the final size is _size=lo.
In this function,loandhiare both value-passed parameters, that is, these two values are destroyed after the function is completed. is a member ofvector. It uses_sizeto determine the number of elements saved._sizeSo what needs to be modified here is , not_size.hi
hiis the right endpoint of the interval to be deleted at the beginning, and afterwhileends, it represents the right endpoint of the remaining elements; before _size is updated, it represents the right endpoint of the element before it is deleted,whileAfter the end, the unupdated _size is meaningless. What the hell is assigning hi to _size
loandhiare local variables (parameters), and their scope is within the function. They are destroyed after the function is executed. It is meaningless to updatehi.
represents the size of the vector _size, which is the value returned by calling v.size(), so _size
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The line where you put the arrow has accumulated the variable lo
Because the elements between [hi,_size] are used to cover the elements in the [lo, _size+lo-hi] interval.
hi increases to _size, and the corresponding lo will increase to _size+lo- hi,
that is, _size+lo-hi is the position of the last element, that is, the new _size value
The code uses lo to mark the position of the last element, so the final size is _size=lo.
In this function,
loandhiare both value-passed parameters, that is, these two values are destroyed after the function is completed.is a member of
vector. It uses_sizeto determine the number of elements saved._sizeSo what needs to be modified here is, not
_size.hihi=_sizeUnreasonableThe meaning of
hiis the right endpoint of the interval to be deleted at the beginning, and afterwhileends, it represents the right endpoint of the remaining elements; before _size is updated, it represents the right endpoint of the element before it is deleted,whileAfter the end, the unupdated _size is meaningless. What the hell is assigning hi to _sizeloandhiare local variables (parameters), and their scope is within the function. They are destroyed after the function is executed. It is meaningless to updatehi.represents the size of the vector _size, which is the value returned by calling v.size(), so _size