According to the memory management mechanism of Linux, a 64-bit system takes up 50% more memory than a 32-bit system. Under the premise of 2G RAM, there is no other difference. Therefore, under this premise, it is best to install 32-bit system. Bit system, this can free up more memory to avoid premature use of swap partitions, resulting in a large number of I/O operations that reduce performance.

64-bit programs always take up more memory than 32-bit programs, for the following reasons:
1. 64-bit pointers need to allocate more memory space (exactly double, this is hard)
2. In a 64-bit environment, struct alignment in memory requires more space. The worst margin is exactly 100% more memory than 32-bit (see example 1 below). Of course, it is rare. Today’s compilers and CPUs The instructions have been optimized well.
3. A 64-bit stack requires more space than a 32-bit stack
4. Also, no more expansion.

For example, you will understand:

cstruct MyStruct1
{
   char m_c;
   void *m_p;
   int m_i;
};

This struct is 12 bytes in 32-bit and 24 bytes in 64-bit.
Another example:

cstruct MyStruct2
{
   void *m_p;
   int m_i;
   char m_c;
};

This struct is also 12 bytes in 32-bit environment, but 16 bytes in 64-bit environment.
The image comparison of these two structs in memory is as follows:

The picture is a comparison under Windows, and the same is true for Linux. After all, the memory is the same. I said 50% more is an average estimate. If it is not optimized during compilation, it may be 100% more.