java的socket端和serversocket端是怎么回事?
PHP中文网
PHP中文网 2017-04-17 11:49:46
0
1
190

我看书上说如何判断socket端是否连接, 自己试了一下, 但是结果没看明白

socket端代码:

    public static void main(String args[])throws Exception
    {
        System.out.println("客户端") ;
        Socket socket = new Socket("localhost" , 8000) ;
        Thread.sleep(10000) ;
        System.out.println(socket.isConnected() + "\t" + !socket.isClosed()) ;
    }

serversocket端代码

    public static void main(String args[])throws Exception
    {
        System.out.println("服务端") ;
        ServerSocket serversocket = new ServerSocket(8000) ;
        Socket s = serversocket.accept() ;
    }

但是结果我不明白,为什么serversocket的程序已经退出了,而socket的程序却显示socket仍然连接?

谁能给我讲一下啊?怎么想也想不通

PHP中文网
PHP中文网

认证高级PHP讲师

Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template
About us Disclaimer Sitemap
php.cn:Public welfare online PHP training,Help PHP learners grow quickly!