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想要匹配的字符串格式为:@xingren @nihao @tolerious@qq.com lalal希望得到的列表项为:['@xingren','@nihao','@tolerious@qq.com']我目前的正则表达式为: /@w+s/g,这个正则只能得到列表:['@xingren','@nihao']而少了@tolerious@qq.com这一项.
@xingren @nihao @tolerious@qq.com lalal
['@xingren','@nihao','@tolerious@qq.com']
['@xingren','@nihao']
@tolerious@qq.com
拥有18年软件开发和IT教学经验。曾任多家上市公司技术总监、架构师、项目经理、高级软件工程师等职务。 网络人气名人讲师，...
哈哈~ 上面的答案傻眼了~ :-D
'@xingren @nihao @tolerious@qq.com lalal @nihao_xx'.match(/@[^\s]+/g) ["@xingren", "@nihao", "@tolerious@qq.com", "@nihao_xx"]
/@\S+/g
'@xingren @nihao @tolerious@qq.com lalal'.match(/@[a-zA-Z@.]+?(?= )/g)
![[Web front-end] Node.js quick start](https://img.php.cn/upload/course/000/000/067/662b5d34ba7c0227.png)
哈哈~ 上面的答案傻眼了~ :-D
/@\S+/g