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var fs = require('fs') fs.open('../src/urls.js', 'w+', function(err, fd) { fs.write(fd, 'const DEV = false\r\n', 0, function(err, bytes) { }) })
这段代码在执行时为什么会提示TypeError:First argument must be file descriptor，明明fd就是open传过来的descriptor啊？求解
TypeError:First argument must be file descriptor
小伙看你根骨奇佳，潜力无限，来学PHP伐。
判断一下是不是打开失败了，如果打开失败，fd肯定就不是文件描述符了
var fs = require('fs') fs.open('../src/urls.js', 'w+', function(err, fd) { if(err!==null){ console.error(err); return; } fs.write(fd, 'const DEV = false\r\n', 0, function(err, bytes) { if(err!==null){ console.error(err); return; } }); })
![[Web front-end] Node.js quick start](https://img.php.cn/upload/course/000/000/067/662b5d34ba7c0227.png)
判断一下是不是打开失败了，如果打开失败，fd肯定就不是文件描述符了