Blockly.Blocks['kjh'] = { init: function() { this.appendDummyInput().appendField('kjh'); this.setOutput(true, null); this.setColour(164); this.setTooltip(''); this.setHelpUrl(''); } }; Blockly.JavaScript['kjh'] = function(block) { var code = 'gdfnh'; return [code, Blockly.JavaScript.ORDER_NONE]; }
请问如何取这段字符串中的xml部分？非常感谢！
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Regarding the problem of taking a piece of xml from a string? -PHP Chinese website Q&A-About the problem of fetching a piece of xml from a string? -PHP Chinese website Q&A
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遇到这种我的一般做法是利用replace+正则来提取。
var t = `Blockly.Blocks['kjh'] = { init: function() { this.appendDummyInput().appendField('kjh'); this.setOutput(true, null); this.setColour(164); this.setTooltip(''); this.setHelpUrl(''); } }; Blockly.JavaScript['kjh'] = function(block) { var code = 'gdfnh'; return [code, Blockly.JavaScript.ORDER_NONE]; } `; var res; t.replace(/]+>[\s\S]*?<\/xml>/,function(e){ res = e; return e }); 这里主要一个正则是关于这段文本如果有回车换行的情况，直接用.*并不能直接匹配，但可用[\s\S]*代替