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错误的意思是 我167的mysqli的 第一个参数不对吗？ 还是哪里有问题呢····不是很明白
ringa_lee
$link=connect2(); var_dump($link);
看看你这个link到底是不是mysqli的实例，即是不是类似
mysqli
function connect2(){ return new mysqli("localhost", "xxx", "xxx", "xxx_db"); }
http://php.net/manual/zh/mysq...
![[Web front-end] Node.js quick start](https://img.php.cn/upload/course/000/000/067/662b5d34ba7c0227.png)
看看你这个link到底是不是
mysqli的实例，即是不是类似http://php.net/manual/zh/mysq...